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A water tank has two taps (Tap1 -Tap2) . Tap -1 can fill a tank in 8 hours and Tap- 2 can empty the tank in 16 hours. How long will they take to fill the tank if both taps are opened simultaneously but tap-2 is closed after 8 hours?

A water tank has two taps (Tap1 -Tap2) . Tap -1 can fill a tank in 8 hours and Tap- 2 can empty the tank in 16 hours. How long will they take to fill the tank if both taps are opened simultaneously but tap-2 is closed after 8 hours? Correct Answer 12

Tap - 1, fills in 1 hr =   1/8 Tap - 2, empties in 1 hr = 1/16 When both taps are open, the tank fills in 1 hr = (1/8 – 1/16) = 1/16 In 8 hrs, the tank fills =   1/16 ×৪ = ½ Remaining = 1 – ½ = ½ ½ is filled by only Tap 1 1/8 is filled by Tap - 1 in 1 hr So, ½ is filled by = (1×8)/2 = 4 hr Total time = 8 + 4 = 12 hr (ans)

Related Questions

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