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4 men can finish work in 6 days, 8 women can finish the same work in 15 days, 10 children can finish the same work in 24 days. How long a team of 1 man, 2 women,and 2 children will take to finish the same work?

4 men can finish work in 6 days, 8 women can finish the same work in 15 days, 10 children can finish the same work in 24 days. How long a team of 1 man, 2 women,and 2 children will take to finish the same work? Correct Answer 15 days 

Given:

4m = 6 days

8w = 15 days

10c = 24 days

Formula used:

Total work = Efficiency × days

Calculations:

⇒ 4m × 6 = 8w × 15 = 10c × 24

⇒ m = 5w = 10c

⇒ m : w : c = 10 : 2 : 1

⇒ Total work = 4m × 6 days

⇒ Total work = 4 × 10 × 6

⇒ Total work = 240

⇒ Efficiency of 1m, 2w and 2c = 1 × 10 + 2 × 2 + 2 × 1

⇒ Efficiency of 1m, 2w and 2c = 10 + 4 + 2

⇒ Efficiency of 1m, 2w and 2c = 16

⇒ Days = 240/16

⇒ Days = 15 days

∴ 1 man, 2 women and 2 children will take15 days to finish the work.

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