Two trains crossed each other in 10 sec. The length of one of the trains is 510 m, while the ratio of their speed is 3 ∶ 2. Approximately in how many second the faster train will cross a platform half its length, if its given speed of slower train is 129.6 km/hr and longer train travels in slower speed?

Two trains crossed each other in 10 sec. The length of one of the trains is 510 m, while the ratio of their speed is 3 ∶ 2. Approximately in how many second the faster train will cross a platform half its length, if its given speed of slower train is 129.6 km/hr and longer train travels in slower speed? Correct Answer 10.83 sec

 The ratio speed of trains are = 3 ∶ 2

∴ Let the speed of train be 3x and 2x respectively 

According to question,

2x = 129.6 km/hr

⇒ 2x = 129.6 × (5/18) m/s

⇒ 2x = 36 or x = 18

∴ 3x = 3 × 18 = 54 m/s

Now, let the length of second train be y m.

⇒ (510 + y)/(54 + 36) = 10 

⇒ 510 + y = 900 

⇒ y = 390 m

∴ Length of faster train = 390 m

Length of platform = 390/2 = 195m

∴ Time taken to cross the platform

⇒ (390 + 195)/54

⇒ 585/54 = 10.83 sec

∴ The faster train will cross a platform in 10.83 sec

Related Questions

The question below is followed by two statements I and II. You have to determine whether the data given is sufficient for answering the question. You should use the data and your knowledge of mathematics to choose the best possible answer. Train A departs at 9 : 20 am and train B departs at 10 : 50 am and they travel towards each other. After how much amount of time will the trains meet? I) Train A travels with a speed of 10 kmph and the difference between the speed of two trains is 6 kmph and both the trains are 160 km apart. II) Train B travels at a speed greater than Train A which travels with 10 kmph by 6kmph separated by a distance of 160 km.