A tap can fill a container in 9 hours. Due to a leakage in its bottom, the container fills up in 10 hours. If the container is full, then in how much time the container will be emptied by the leakage?

A tap can fill a container in 9 hours. Due to a leakage in its bottom, the container fills up in 10 hours. If the container is full, then in how much time the container will be emptied by the leakage? Correct Answer 90 hrs

Given:

A tap can fill a container in 9 hours

With leakage container can be filled in 10 hours

Concept:

If a tap can fill a tank in x hours, then the tank filled by the tap in 1 hour = 1/x of the total tank.

Calculation:

Part of the container emptied by the leak in 1 hours = (1/9) – (1/10)

⇒ (10 – 9)/90

⇒ 1/90

∴ The required time is 90 hours.

Related Questions

The following questions have three statements. Study the question and the statements and decide which of the statement(s) is/are necessary to answer the question. In how many hours tap B can fill the completely empty tank? Statement I: The inlet tap A and the outlet tap C working simultaneously takes 40 hours to fill the tank. Statement II: Efficiency of inlet tap B is equal to efficiency of outlet tap C or 62.5% of the efficiency of inlet tap A. Statement III: The outlet tap C can empty a half filled tank in 12 hours.