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A cyclist leaves A at 10 am and reaches B at 11 am. Starting from 10:01 am, every minute a motorcycle leaves A and moves towards B. Forty-five such motorcycles reach B by 11 am. All motorcycles have the same speed. If the cyclist had doubled his speed, how many motorcycles would have reached B by the time the cyclist reached B?

A cyclist leaves A at 10 am and reaches B at 11 am. Starting from 10:01 am, every minute a motorcycle leaves A and moves towards B. Forty-five such motorcycles reach B by 11 am. All motorcycles have the same speed. If the cyclist had doubled his speed, how many motorcycles would have reached B by the time the cyclist reached B? Correct Answer 15

Calculation:

Let the speed of a motorcycle be a and speed of cyclist be b

There are 45 motorcycles reaches at 11 am

⇒ Last motorcycle reached B at 11 am

⇒ Last motorcycle left A at 10:15 am

Now the speed of cyclists is doubled.

⇒ Now it will reach point B at half time

⇒ Now the last cycle left A at 10:30 am 

From 10:01 to 10:15, the number of motorcycles that can be left for B is 15

∴ Maximum 15 motorcycles will reach at the time of cyclist.

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