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Doctors Medicines MCQs Q&A

Product X is produced by mixing chemical A and chemical B in the ratio of 5 : 4. Chemical A is prepared by mixing two raw materials, P and Q, in the ratio of 1 : 3. Chemical B is prepared by mixing raw materials, Q and R, in the ratio of 2 : 1. Then the final mixture is prepared by mixing 8640 units of product X with water. If the concentration of the raw material Q in the final mixture is 50%, how much water had been added to product X?

Product X is produced by mixing chemical A and chemical B in the ratio of 5 : 4. Chemical A is prepared by mixing two raw materials, P and Q, in the ratio of 1 : 3. Chemical B is prepared by mixing raw materials, Q and R, in the ratio of 2 : 1. Then the final mixture is prepared by mixing 8640 units of product X with water. If the concentration of the raw material Q in the final mixture is 50%, how much water had been added to product X? Correct Answer 3680

Calculation:

Product X is produced by mixing chemical A and B in the ratio 5 : 4.

Hence, 5/9th of product X is chemical A and 4/9th of product X is chemical B.

Chemical A has P and Q in a ratio 1 : 3.

∴ 3/4th of A is Q.

∴ the proportion of Q in product X from chemical A = 5/9 × 3/4

Chemical B has Q and R in a ratio 2 : 1.

∴ 2/3th of B is Q.

∴ the proportion of Q in product X from chemical B = 4/9 × 2/3

Adding the two, the proportion of Q in Product X

⇒ 5/9 × 3/4 + 4/9 × 2/3

⇒ 77/108

The final mixture is obtained by mixing 8640 units of product X with water.

∴ total Q in X = 77/108 × 8640

⇒ 6160

Total Q in the final mixture

⇒ 6160 × 2

⇒ 12320

The proportion of Q in water is 0.

Units of water added = 12320 – 8640

⇒ 3680 units.

3680 units of water had been added to product X.

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