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A, B and C were three body builder having the same working rate, they were work out together in a gym for 60 days. In the course of work, all of them remained absent for few days. A was absent for 20 days more than B and C did one third of the total work out. How many days more than C was A absent?

A, B and C were three body builder having the same working rate, they were work out together in a gym for 60 days. In the course of work, all of them remained absent for few days. A was absent for 20 days more than B and C did one third of the total work out. How many days more than C was A absent? Correct Answer 10 days

Given∶

Total No. of days to work out = 60

A was absent for 20 days more than B.

C did 1/3 of total work out.

Formula Used∶

Concept of Linear Equations.

Calculation∶

Let 'k' be the part of the work out that body builders can do in 1 day. And,

x - 20, x and y be the number of days for which they remained absent. Then,

According to Question,

( x - 20) k + (x) k = 2/3 or

⇒ k = 2/3      (1)

and (y) k = 1/3

or k = 1/3 y

Put k = 1/3 y in eq.      (1)

 × 1/3 y = 2/3

⇒ 2x - 20 = 2y

⇒ x - 10 = y

The required no. of days = y - (x - 20) = x - 10 - (x - 20) = x - 10 - x + 20 = 10

Thus, A was absent 10 more days than C.

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