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A, B, and C start from the same place X and travel at 16 km/h, 40 km/h 56 km/h respectively. If B starts t hours after A has started, how many hours after B has started should C start, so that both B and C overtake A at the same time?

A, B, and C start from the same place X and travel at 16 km/h, 40 km/h 56 km/h respectively. If B starts t hours after A has started, how many hours after B has started should C start, so that both B and C overtake A at the same time? Correct Answer 4t/21

Given:

The speed of A, B, and C is 16 km/h 40 km/h and 56 km/h respectively

Concept:

Speed = Distance/Time

Calculation:

Let C start a hours after B started, 

⇒ When C has started till then B cover the distance = 40a and A will cover the distance = 16 × (a + t)

⇒ 16 × (a + t)/(56 - 16) = {16 × (a + t) - 40a}/(40 - 16)

⇒ a = 4t/21

∴ The required result will be 4t/21.

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