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A student walked 110 m to the East to look for his class teacher, and then he turned right and walked 40 m. Then he turned right again, and after walking 50 m he reached his class teacher's staffroom. His class teacher was not there. From there he walked 120 m to his north and met his class teacher. How far from the starting point did he meet his class teacher?

A student walked 110 m to the East to look for his class teacher, and then he turned right and walked 40 m. Then he turned right again, and after walking 50 m he reached his class teacher's staffroom. His class teacher was not there. From there he walked 120 m to his north and met his class teacher. How far from the starting point did he meet his class teacher? Correct Answer 100 m

The diagram below shows the path followed by Student:

Here A is the Starting point and E is Ending point

The shortest distance to meet the teacher by student is 

AE² = AF² + EF²

AE² = 60² + 80²  (110m - 50m = 60m  = AF) 

AE² = 10000

AE = √10000 = 100m

So the shortest distance is 100m

Hence, the correct answer is "100m'.

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