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A Policeman spots a thief 200 meters away and starts chasing him. How far would the thief have run before being caught if their speeds are 20 km/h and 16 km/h respectively.

A Policeman spots a thief 200 meters away and starts chasing him. How far would the thief have run before being caught if their speeds are 20 km/h and 16 km/h respectively. Correct Answer 800 m

Given:

The Policeman is 200 meters away from the thief

Policeman's speed is 20 km/h

Theif's speed is 16 km/h

Formula used:

Distance = Speed × Time

Calculation:

Let the distance where the Policeman will catch the thief be D.

Now distance travelled by the Policeman to catch the thief = (D + 200) meters

Distance travelled by the thief = D meters

According to the question, the Policeman can catch the thief 

So, (D + 200)/{(20 × (5/18)} = D/{16 × (5/18)}

⇒ (D + 200)/20 = D/16

⇒ 800 + 4D = 5D

⇒ D = 800

∴ The thief have run before being caught is 800 meters.

Hint

x km/h = {x × (5/18)} m/s

x m/s = {x × (18/5)} km/h

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