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There are 3 bowls and 5 nuts. All these nuts are to be distributed into three bowls where any bowl can contain any number of nuts. In how many ways these nuts can be distributed into these bowls if all the bowls and all the nuts are different?

There are 3 bowls and 5 nuts. All these nuts are to be distributed into three bowls where any bowl can contain any number of nuts. In how many ways these nuts can be distributed into these bowls if all the bowls and all the nuts are different? Correct Answer 3<sup>5</sup>

All the nuts and all the bowls are different.

∴ Required number of ways of distribution = 3 × 3 × 3 × 3 × 3 = 35

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