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Three friends A, B and C shared chocolates from a bowl. A took 1/3rd of the chocolates, but returned four to the bowl. B took 1/4th of what was left but returned three chocolates to the bowl. C took half of the remainder but return two back into the bowl. If the bowl has 17 chocolates left, how many chocolates were originally there in the bowl ?

Three friends A, B and C shared chocolates from a bowl. A took 1/3rd of the chocolates, but returned four to the bowl. B took 1/4th of what was left but returned three chocolates to the bowl. C took half of the remainder but return two back into the bowl. If the bowl has 17 chocolates left, how many chocolates were originally there in the bowl ? Correct Answer 48

Given:

Chocolates have taken by A =1/3 of total

Left chocolate = 17

Calculations:

Let, the number of chocolates = x

⇒ After taking 1/3 of chocolate remaining chocolate = 2x/3

⇒ After adding 4 chocolate = (2x/3) + 4

⇒ Taking 1/4 chocolate by b, remaining chocolate =1/4(2x/3) + 4} = (x/6) + 1

⇒ After returning 3 chocolate to bowl ramining chocolate in bowl = (2x/3) + 4 - {(x/6) + 1} + 3 = (x/2) + 6

⇒ c takes half of the chocolate, than reaming chocolate = 1/2{(x/2) + 6} = (x/4) + 3

⇒ After returning 2 chocolate, chocolates in bowl = (x/4) + 3 + 2

⇒ (x/4) + 5 = 17

⇒ x/4 = 12

⇒ x = 48

∴ 48 chocolates were originally there in the bowl.

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