The upper part of a tree is broken by the wind makes an angle of 60° with the ground and the distance from the root to the point where the top of the tree touches the ground is 15 cm. What was the height of the tree?

The upper part of a tree is broken by the wind makes an angle of 60° with the ground and the distance from the root to the point where the top of the tree touches the ground is 15 cm. What was the height of the tree? Correct Answer 15(2 + √3) cm

[ alt="CHSL 1 30Q Reviewed 6" src="//storage.googleapis.com/tb-img/production/19/04/CHSL_1%20_%2030Q%20Reviewed%206.PNG">

Let the tree is broken at point D,

⇒ AD = BD = x(let)

In ΔBDC,

⇒ tan60° = DC/BC = DC/15

⇒ √3 = DC/15

⇒ DC = 15√3 cm

Also, sin60° = DC/BD

⇒ √3/2 = 15√3/BD

⇒ BD = 30 cm