The upper part of a tree broken over by the wind make an angle of 30 ° with the ground. The distance from the foot of the tree to the point, where the top point touches the ground is 20√3m. Then, find the height of the tree?

The upper part of a tree broken over by the wind make an angle of 30 ° with the ground. The distance from the foot of the tree to the point, where the top point touches the ground is 20√3m. Then, find the height of the tree? Correct Answer 60 m

Given:

AB = 20√3 m

Formula Used:

Calculation:

[ alt="F53 Harshit 12-5-2021 Swati D5" src="//storage.googleapis.com/tb-img/production/21/05/F53_Harshit_12-5-2021_Swati_D5.png" style="width: 128px; height: 183px;">

Suppose the total height of the tree is AB’.

The distance from the foot of the tree to the point, where the top point touches the ground = AB = 20√3 m

In ΔABC; tan30° = AC/AB

⇒ 1/√3 = AC/20√3

⇒ AC = 20 m

Now, sin30° = AC/CB

⇒ ½ = 20/CB

⇒ CB = 40 m