VHDL code SUM < = A XOR B Carry < = A AND B where A and B are inputs, represents

VHDL code SUM < = A XOR B Carry < = A AND B where A and B are inputs, represents Correct Answer Half adder

Clearly this is the code of a Half adder where:

  • the Sum bit is the XOR of the two input bits
  • the carry bit is simply the AND of the two input bits

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A half adder circuit is basically made up of an AND gate and an XOR gate as shown below:

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  • A half adder is also known as XOR gate because XOR is applied to both inputs to produce the sum
  • Half adder can add only two bits (A and B) and has nothing to do with the carry
  • If the input to a half adder has a carry, then it will neglect it and adds only the A and B bits
  • That means the binary addition process is not complete and that's why it is called a half adder


Sum (S) = A⊕B, Carry = A.B

INPUTS

OUTPUTS

A

B

Sum

CARRY

0

0

0

0

0

1

1

0

1

0

1

0

1

1

0

1

 

Related Questions

In AES, to make the s-box, we apply the transformation b’_i = b_i XOR b_(i+4) XOR b(i+5) XOR b_(i+6) XOR b_(i+7) XOR c_i What is c_i in this transformation?
In AES, to make the s-box, we apply the transformation – b’i = bi XOR b(i+4) XOR b(i+5) XOR b(i+6) XOR b(i+7) XOR ci What is ci in this transformation?
The inverse s-box permutation follows, b’_i = b_(i+2) XOR b(i+5) XOR b_(i+7) XOR d_i Here d_i is
The inverse s-box permutation follows, b’i = b(i+2) XOR b(i+5) XOR b(i+7) XOR di Here di is –