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The inverse s-box permutation follows, b’i = b(i+2) XOR b(i+5) XOR b(i+7) XOR di Here di is –

The inverse s-box permutation follows, b’i = b(i+2) XOR b(i+5) XOR b(i+7) XOR di Here di is – Correct Answer di is the ith bit of a byte ‘d’ whose hex value is 0x05

The value of ‘d’ is 0x05.

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