What is the value of (i2 + i4 + i6 +... + i2n), Where n is even number.
What is the value of (i2 + i4 + i6 +... + i2n), Where n is even number. Correct Answer 0
Concept:
i2 = -1
i3 = - i
i4 = 1
i4n = 1
Calculation:
We have to find the value of (i2 + i4 + i6 +... + i2n)
(i2 + i4 + i6 +... + i2n) = (i2 + i4) + (i6 + i8) + …. + (i2n-2 + i2n)
= (-1 + 1) + (-1 + 1) + …. (-1 + 1)
= 0 + 0 + …. + 0
= 0
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Feb 20, 2025