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A travels from Pune to Mumbai and B from Mumbai to Pune which is 200 km apart. The speed of A is 20 km/hr more than B. Both meet somewhere in the middle in 2 hours. Find the time required to travel for C from Pune to Mumbai if the speed of C is 10 km/hr more than B.

A travels from Pune to Mumbai and B from Mumbai to Pune which is 200 km apart. The speed of A is 20 km/hr more than B. Both meet somewhere in the middle in 2 hours. Find the time required to travel for C from Pune to Mumbai if the speed of C is 10 km/hr more than B. Correct Answer 4 hours

Solution:

Given data :

Distance between Pune to Mumbai (D) = 200 km

Speed of A (A) – Speed of B (B) = 20 km/hr

Meeting time while travelling towards each other = 2 hours

Speed of C (C) = (B + 10) km/hr

Formula used :

Speed = Distance/time

Relative speed A and B (moving towards each other) = (Speed)A + (Speed)B

Calculation :

Let, speed of B = x km/hr

Speed of A = (x + 20) km/hr

The relative speed of A and B while travelling towards each other = A + B

⇒ x + x + 20

⇒ (2x + 20) km/hr

Relative Time to cover distance = Distance/(Relative time)

⇒ 2 = 200/(2x + 20)

⇒ 2 × (2x + 20) = 200

⇒ 4x + 40 = 200

⇒ 4x = 160

⇒ x = 40 km/hr

⇒ Speed of A = x + 20 = 40 + 20 = 60 km/hr

⇒ Speed of B = x = 40 km/hr

⇒ Speed of C = B + 10

⇒ 40 + 10 = 50 km/hr

Time required for C to travel from Pune to Mumbai = Distance/Speed

⇒ 200/50 = 4 hours

 

∴ C will take 4 hours for travelling from Pune to Mumbai.

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