The sleeper density of a broad gauge track is (M + 7) in metric units, where M is length of rail in metres. The number of sleepers for 1.024 km length of track is:

The sleeper density of a broad gauge track is (M + 7) in metric units, where M is length of rail in metres. The number of sleepers for 1.024 km length of track is: Correct Answer 1600

On Indian railways standard length of BG rail = 13 m 

So, total no. of rail required in 1.024 km or 1024 m

= 1024/13 = 78.78 = 80 (in round figure)

Sleeper density = M + 7

M = length of rail

So, sleeper density = 13 + 7 = 20

No. of sleepers = 20 × 80 = 1600

Related Questions

How far is point 'R' from Point 'T'? Statement (I): Point 'R' is 5 metres to the north of point 'M'. Point 'U' is 4 metres to the east of point 'R'. Point 'T' is to the west of point 'R' such that points 'U' 'R' and 'T' form a straight line of  metres. Statement (II): Point 'Z' is metres to the south of point 'T'. Point 'U' is  metres to the east of point 'T'. Point 'M' is  metres to the east of point 'Z'. Point 'R' is  metres to the north of point 'M'. Point 'R' lies on the line formed by joining points 'T' and 'U'.