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A train leaves station A towards station B at the speed of 50 km/hr. After half an hour, another train leaves station B towards station A at 150 km/hr. The distance between the stations is 725 km. The distance of the point from station A where the two trains are to meet is:

A train leaves station A towards station B at the speed of 50 km/hr. After half an hour, another train leaves station B towards station A at 150 km/hr. The distance between the stations is 725 km. The distance of the point from station A where the two trains are to meet is: Correct Answer 200 km

Given:

The speed of train which leaves station A = 50 km/hr 

The speed of train which leaves station B = 150 km/hr

The distance between the two stations A and B = 725 km

Formula used:

Distance = Speed × Time

Relative Speed ( in opposite direction) = Speed I + Speed II 

Meeting Time = Distance between the trains/ Relative Speed 

Solution:

Relative speed of both the trains going in opposite direction = 50 km/h + 150 km/h

⇒ 200 km/h

Distance between the trains after half an hour of train leaving station A =  725 km - 50 km/h × 1/2 hours = 700 km

Meeting time = 700 km / 200 km/h = 7/2 hours

∴ Distance from station A where two trains are to meet = 25 km + 50 km/h × 7/2 hours = 200 km

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