If Δp is an increment of pressure on a normally consolidated saturated soil mass, as per Terzaghi's theory at the instant of application of pressure increment i.e., When time t = 0, what is the pore pressure developed in the soil mass?
If Δp is an increment of pressure on a normally consolidated saturated soil mass, as per Terzaghi's theory at the instant of application of pressure increment i.e., When time t = 0, what is the pore pressure developed in the soil mass? Correct Answer Equal to Δp
Concepts:
When stress of ∆p has been applied over the ground surface then at t = 0, the pore pressure will increase by an amount equal to the applied stress. Since the applied (total) stress and the pore pressure increase by equal amounts, there will be no change in effective stress.
The pore pressure u at any depth z below the ground surface is given as:
U = Ui + ∆U = γw z + ∆p.
Therefore, the excess pore water pressure developed will be equal to Δp at t = 0 (at the instant of additional load application).
Further, the excess pore water pressure developed in soil is given as:
ΔU = Ui – Ut
Ut is the pore water pressure at any time
Ui initial pore water pressure.
So, the excess pore water pressure developed will be equal to Δp at t = 0 (at the instant of additional load application)
