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Given below are two quantities named A & B. Based on the given information; you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answers. Quantity A∶ Percentage of water in the final mixture, when a mixture of 20 litre having 80% pure milk is mixed with 10 litre pure milk. Quantity B∶ Profit percentage when a 50 litre of pure milk is mixed with 10 litre of water and the mixture is sold at the cost price of milk.

Given below are two quantities named A & B. Based on the given information; you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answers. Quantity A∶ Percentage of water in the final mixture, when a mixture of 20 litre having 80% pure milk is mixed with 10 litre pure milk. Quantity B∶ Profit percentage when a 50 litre of pure milk is mixed with 10 litre of water and the mixture is sold at the cost price of milk. Correct Answer Quantity A < Quantity B

Quantity A∶

Quantity of Mixture = 20 litre

Quantity of Milk = 80% of 20 litre = 16 litre

⇒ Quantity of Water = 20 – 16 = 4 litre

Pure milk added to the mixture = 10 litre

Total quantity of milk now = 16 + 10 = 26 litre

Quantity of Water remains = 4 litre

Percentage of water in the final mixture = 4/30 × 100 = 40/3 %

Quantity B∶

Let the cost price of one litre pure milk = Rs. 1 per litre

The cost price of 50 litre pure milk = Rs. 50

10 litre water is added and the mixture is sold at the cost price of the pure milk

⇒ It is sold at the cost price of 60 litre milk = Rs. 60

Selling price = Rs. 60

Cost price = Rs. 50

Profit = 60 – 50 = Rs. 10

Profit percentage = 10/50 × 100 = 20%

∴ Quantity A < Quantity B

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