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A least number, P is divided by 5, 7 and 11 successively in order to get remainders of 1, 3 and 2 respectively. What will be the successive remainders when P is divided by 7, 6 and 4?

A least number, P is divided by 5, 7 and 11 successively in order to get remainders of 1, 3 and 2 respectively. What will be the successive remainders when P is divided by 7, 6 and 4? Correct Answer 2, 1, 3

Calculation:

For first condition,

Divisor

Dividend

Remainder

5

94 × 5 + 1 = 471 (P)

1

7

13 × 7 + 3 = 94

3

11

11 × 1 + 2 = 13

2

 

1

 


⇒ Dividend P is 471.

For second condition,

Divisor  

Dividend  

Remainder  

7

471

2

6

67

1

4

11

3

 

2

 


∴ Required successive remainders is 2, 1 and 3.

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