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A truck approaches a tunnel inside a tunnel a rat is sitting at a point which is 4/9th of the distance of the tunnels measured from the entrance. When the truck horns the rat moves towards the entrance and truck catches the rat at the entrance and if the rat runs towards the exit then also truck catch the rat at the exit. The speed of truck is how much times the speed of rat?

A truck approaches a tunnel inside a tunnel a rat is sitting at a point which is 4/9th of the distance of the tunnels measured from the entrance. When the truck horns the rat moves towards the entrance and truck catches the rat at the entrance and if the rat runs towards the exit then also truck catch the rat at the exit. The speed of truck is how much times the speed of rat? Correct Answer 9 times

According to the given question

Given:

Rat is sitting at 4/9th of the distance of the tunnel

Formula used/Concept used:

Concept of Ratio and proportion

Calculation:

Let the distance of the tunnels is PQ where P is entrance and Q is exit and the initial position of truck and rat will be

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When rat runs towards the entrance the truck will catch the rat at P

∴ Truck reaches to entrance when rat cover 4/9th of distance

Let assume the rat is runs towards the B and covers 4/9th of distance then the truck will reach to the entrance of the tunnel.

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Now, Truck will catch the rat at exit Q

∴ In the time in which rat covers 1/9th of distance truck will cover the whole distance

So, the ratio of distance covered by Rat and Truck = 1 ∶ 9

Then the ratio of speed of Rat and Truck = 9 ∶ 1

So the speed of truck is 9 times the speed of rat.

Hence, option (3) is correct

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