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Two friends- Seema and Reena go for morning walk for one month. The weight of Seema was 15 kgs more than Reena one month ago but the weight of Reena was 5 kgs more than the weight of Seema after one month. After a month, by what amount did the average weight of Reena got reduced when compared to Seema?

Two friends- Seema and Reena go for morning walk for one month. The weight of Seema was 15 kgs more than Reena one month ago but the weight of Reena was 5 kgs more than the weight of Seema after one month. After a month, by what amount did the average weight of Reena got reduced when compared to Seema? Correct Answer 5

Given:

The weight of Seema was 15 kg more than Reena one month ago

The weight of Reena was 5 kg more than the weight of Seema after one month

Formula:

Average of n numbers a1, a2, ..., an = (a1 + a2 + ... + an)/n

Calculation:

Let the weights of Seema and Reena before a month be x + 25 and x respectively

Let the weights of Seema and Reena after a month be y and y + 5 respectively

Average weight of Seema = (x + y + 15)/2

Average weight of Reena = (x + y + 5)/2

Difference in average weights of Reena and Seema = –

⇒ 10/2 = 5

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