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Pipe A can fill a tank 18 hours while pipe B can empty a tank in 12 hours. Both the pipes are opened when the tank was completely filled. Pipe B is closed after 12 hours. If pipe A along with C can fill the tank, which is emptied in 4 hours, then find the time taken by pipe C to fill the completely empty tank alone? 

Pipe A can fill a tank 18 hours while pipe B can empty a tank in 12 hours. Both the pipes are opened when the tank was completely filled. Pipe B is closed after 12 hours. If pipe A along with C can fill the tank, which is emptied in 4 hours, then find the time taken by pipe C to fill the completely empty tank alone?  Correct Answer 36 hours

Given:

Pipe A can fill a tank 18 hours.

Pipe B can empty a tank in 12 hours.

Formula Used:

Total work = Efficiency × Time taken

Calculation:

Total Work done = LCM of days = 36 

 

Days

Efficiency

A

18

2

B

12

3

 

 

 

 

 

The total capacity of the tank = 36 units

According to the question:

The tank empty in 12 hours when both pipes are opened = (3 - 2) × 12 = 12 units

Let the efficiency of C be x unit/hour

Time taken to fill the empty tank by A and C together = 4 hours 

⇒ (x + 2) × 4 = 12

⇒ x = 1 unit/hour

Time taken by Pipe C to fill the tank alone = 36/1 = 36 hours

∴ Time taken by Pipe C to fill the tank alone is 36 hours.

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