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When Rolle's Theorem states is verified for f (x) on [a, b] then there exists c such that

When Rolle's Theorem states is verified for f (x) on [a, b] then there exists c such that Correct Answer c <span class="math-tex">\(\rm \epsilon \)</span> (a, b) such that f'(c) = 0

Explanation:

(Rolle’s Theorem) : Let f  : → R be continuous on and differentiable on (a, b), such that f (a) = f (b), where a and b are some real numbers. Then there exists some c in (a, b) such that f′ (c) = 0. 

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