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Pipe A can fill an empty tank in 30 minutes, Pipe B can empty the same filled tank in 2 hours and Pipe C can empty the same filled tank in 5 hours. If all these are opened together when the tank is empty, then in how many hours will the tank be filled?

Pipe A can fill an empty tank in 30 minutes, Pipe B can empty the same filled tank in 2 hours and Pipe C can empty the same filled tank in 5 hours. If all these are opened together when the tank is empty, then in how many hours will the tank be filled? Correct Answer <span class="math-tex">\(\frac{10}{13}\)</span>

Given:

Pipe A can fill in 30 m

Pipe B and Pipe C can empty in 2 h and 5 h

Concept used:

Total work = LCM of time taken by pipes individually

Calculation:

LCM of 1/2, 2, and 5 = 10

So, Efficiency of A = 20

Efficiency of B = 5

Eifficency of C = 2

Effective efficiency = 20 - 5 - 2 = 13

Time taken by three pipes = 10/13 hours

∴ The tank will be filled in 10/13 hours

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