The Order of Differential equation whose solution is y = msinx + ncosx where m, n are arbitrary constants
The Order of Differential equation whose solution is y = msinx + ncosx where m, n are arbitrary constants Correct Answer 2
dy/dx = mcosx - nsinx
d2y/dx2 = - msinx - ncosx
= - (msinx + ncosx)
∴ d2y/dx2 = - y
Highest derivative is d2y/dx2 and order is 2
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Feb 20, 2025