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4 taps are fitted in a tank in which some are inlet taps and some are outlet taps. Each inlet tap can fill the tank in 24 hours and each outlet tap can empty the tank in 8 hours. Find the number of outlet taps if the whole tank is emptied in 3 hours when all the 4 taps are open.

4 taps are fitted in a tank in which some are inlet taps and some are outlet taps. Each inlet tap can fill the tank in 24 hours and each outlet tap can empty the tank in 8 hours. Find the number of outlet taps if the whole tank is emptied in 3 hours when all the 4 taps are open. Correct Answer 3

Given:

Total number of taps = 4

Time taken by each inlet tap to fill the tank = 24 hours

Time taken by each outlet tap to empty the tank = 8 hours

Total time taken to empty the tank = 3 hours

Concept used:

Total work = Time taken × Efficiency

And, Total efficiency = efficiency of intlet taps – efficiency of outlet taps

Calculation:

Let total number of inlet taps be x

Total number of outlet taps be (4 – x)

L.C.M of 24 and 8 = 24 units = Total work

Total time taken to empty the tank = 3 hours

Efficiency of all 4 taps = 24/3 = -8 units

Here, negative sign in efficiency shows tank is emptying

Efficiency of each inlet tap = 24/24 = 1 units

Now, Efficiency of x inlet taps = x

Efficiency of each outlet tap = 24/8 = 3 units

Efficiency of (4 - x) outlet taps = (12 - 3x)

So, Total efficiency of 4 taps = efficiency of inlet taps – efficiency of outlet taps

⇒ Total efficiency of 4 taps = x – (12 – 3x)

So, x – (12 – 3x) = -8

⇒ 4x – 12 = -8

⇒ 4x = 4

⇒ x = 1

⇒ Outlet taps = (4 – 1) = 3

∴ The number of outlet taps is 3

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