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At a wedding, the guest may have ice creams or custard with their dessert. Total number of guests present in the wedding is 250. 120 guests had Ice-Cream, 100 guests had custard and 20 guests had both ice cream and custard. Then, find the number of the guest who hadn’t ice cream or custard with their dessert?

At a wedding, the guest may have ice creams or custard with their dessert. Total number of guests present in the wedding is 250. 120 guests had Ice-Cream, 100 guests had custard and 20 guests had both ice cream and custard. Then, find the number of the guest who hadn’t ice cream or custard with their dessert? Correct Answer 50

Given:

Total number of guests in wedding = 250

Guest had custard = 100

Guest had Ice-Cream = 120

Guest had Ice Cream and Custard = 20

Concept:

Venn diagram

Calculation:

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Total number of guests in wedding = 250

Guest had custard = 100

Guest had Ice-Cream = 120

Guest had Ice Cream and Custard = 20

Therefore, guests had only custard = (100 – 20) = 80

The guests had only Ice-creams = (120 – 20) = 100

∴ The guest who hadn’t ice cream or custard with their dessert = 250 – (100 + 80 + 20)

⇒ 250 – 200

⇒ 50

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