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There are 48 workers and 2 managers in a company. The salary of one worker of them is twice the salary of another worker. If these 2 workers are replaced by 2 managers whose salaries are Rs. 32000 and Rs. 22000, the average salary of workers increases by Rs. 500. Find the total salary of replaced two workers. 

There are 48 workers and 2 managers in a company. The salary of one worker of them is twice the salary of another worker. If these 2 workers are replaced by 2 managers whose salaries are Rs. 32000 and Rs. 22000, the average salary of workers increases by Rs. 500. Find the total salary of replaced two workers.  Correct Answer Rs. 30000 

Given:

Total number of workers = 48

Number of managers = 2

Formula used:

Sum of observations = Average × Number of observations

Calculation:

Let the average salary of 48 workers be x.

Sum = 48x

Let the salary of one worker be y

Another person salary = 2y

According to the question, we have

⇒ 48x - (y + 2y) + 32000 + 22000 = 48(x + 500)

⇒ 48x - 3y + 54000 = 48x + 24000

⇒ 30000 = 3y

⇒ y = 10000

Another person salary = 2y

⇒ Another person salary = 2 × 10000

⇒ Another person salary = 20000

Total salary = 10000 + 20000

Total salary = 30000

∴ The total salary of the replaced workers is Rs. 30000.

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