An object is projected at an angle θ into the atmosphere using a complex mechanism. The projectile travels with a specific velocity 'u' and makes an angle θ with the horizontal plane. In order for the projectile to travel maximum distance, the value of θ should be
An object is projected at an angle θ into the atmosphere using a complex mechanism. The projectile travels with a specific velocity 'u' and makes an angle θ with the horizontal plane. In order for the projectile to travel maximum distance, the value of θ should be Correct Answer 45<sup>0</sup>
The resistance offered by air to the movement of projectile is neglected.
The maximum distance travelled by projectile is given by
R = (u2 sin 2θ)/g
where g is acceleration due to gravity.
In the above formula the initial height of projectile is not considered. It is assumed that the projectile is launched from a flat ground.
For the specific velocity 'u', R is maximum when sin 2θ = 1
This implies 2θ = 900 ⇒ θ = 900/2 = 450
Thus, the projectile to travel maximum distance at θ = 450
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Feb 20, 2025