The hydraulic radius for flow in a rectangular duct of cross-sectional dimension H, W is

A $$\sqrt {\frac{{{\text{HW}}}}{\pi }} $$
B $$\frac{{{\text{HW}}}}{{2{{\left( {{\text{H}} + {\text{W}}} \right)}^2}}}$$
C $$\frac{{{\text{HW}}}}{{4{{\left( {{\text{H}} + {\text{W}}} \right)}^2}}}$$
D $$\frac{{2{\text{HW}}}}{{\left( {{\text{H}} + {\text{W}}} \right)}}$$

Correct Answer: $$\frac{{{\text{HW}}}}{{2{{\left( {{\text{H}} + {\text{W}}} \right)}^2}}}$$

Bissoy MCQ
#Chemical Engineering #Fluid Mechanics

Related Questions

Rectangular ABCD is similar to rectangular EFGH. The length of each side of rectangle EFGH is 24 times the length of corresponding side of rectangle ABCD.The perameter of rectangular ABCD is 120 feet.What is the parameter of rectangular paramaeter EFGH?
A 288feet
B 345.6feet
C 576feet
D 691.2feet
The most economical section of a rectangular channel is one which has hydraulic mean depth or hydraulic radius equal to
A Half the depth
B Half the breadth
C Twice the depth
D Twice the breadth
The equivalent diameter for flow through a rectangular duct of width B and height H is
A $$\frac{{{\text{HB}}}}{{2\left( {{\text{H}} + {\text{B}}} \right)}}$$
B $$\frac{{{\text{HB}}}}{{{\text{H}} + {\text{B}}}}$$
C $$\frac{{2{\text{HB}}}}{{{\text{H}} + {\text{B}}}}$$
D $$\frac{{4{\text{HB}}}}{{{\text{H}} + {\text{B}}}}$$
The area of a rectangular field is 52000 sq. meters. This rectangular area has been drawn on a map to the scale 1 cm to 100 m. The length is shown as 3.25 cm on the map. The breadth of the rectangular field in the map is -
A 1.6 m
B 160 m
C 160 cm
D 1.6 cm
The hydraulic mean depth or the hydraulic radius is the ratio of
A Area of flow and wetted perimeter
B Wetted perimeter and diameter of pipe
C Velocity of flow and area of flow
D None of these
The ratio of the hydraulic radius to the diameter of the channel, for maximum mean velocity of flow in a circular channel, in open channel flow is
A 0.3
B 0.9
C 0.03
D 0.66
The ratio of the depth of flow to the hydraulic radius for the most economical trapezoidal section, in open channel flow is
A 0.5
B 1
C 1.5
D 2
In open channel flow in a rectangular channel, the ratio between the critical depth and the initial depth, when a hydraulic jump occurs is
A 0.5
B 0.84
C 1.84
D 1.25
A snapshot measures 5/2 inches by 15/8 inches. It is to be enlarged so that the longer dimension will be 4 inches. What will be the length of the enlarged shorter dimension then?
A 2 : 1
B 4 : 3
C 1 : 2
D 4 :2
If 'x' is the depth of flow in an open channel of large width, then the hydraulic radius is equal to
A x
B $$\frac{{\text{x}}}{2}$$
C $$\frac{{\text{x}}}{3}$$
D $$\frac{{2{\text{x}}}}{3}$$

Next steps