Related Questions

The most economical section of a trapezoidal channel is one which has hydraulic mean depth equal to
A $$\frac{1}{2}$$ × depth
B $$\frac{1}{2}$$ × breadth
C $$\frac{1}{2}$$ × sloping side
D $$\frac{1}{4}$$ × (depth + breadth)
The most economical section of a rectangular channel is one which has hydraulic mean depth or hydraulic radius equal to
A Half the depth
B Half the breadth
C Twice the depth
D Twice the breadth
The ratio of the hydraulic radius to the diameter of the channel, for maximum mean velocity of flow in a circular channel, in open channel flow is
A 0.3
B 0.9
C 0.03
D 0.66
In open channel flow in a rectangular channel, the ratio between the critical depth and the initial depth, when a hydraulic jump occurs is
A 0.5
B 0.84
C 1.84
D 1.25
The most economical channel section for the fluid flow is the one for which the discharge is maximum for a given cross-sectional area. Vertical velocity distribution in an open channel for laminar flow can be assumed to be
A Parabolic
B Hyperbolic
C Straight line
D None of these
The ratio of width to depth for the most economical rectangular section in open channel flow is
A 0.5
B 1
C 1.5
D 2
The ratio of the depth of flow to the diameter of the channel for maximum discharge in a circular channel in open channel flow is
A 0.1
B 0.55
C 0.95
D 1.85
Normal depth in open channel flow is the depth of flow in the channel
A Corresponding to uniform flow
B Measured normal to the channel bed
C Corresponding to steady flow
D None of these
A rectangular channel has cross sectional area of 50 m2 If the channel section is to be most economical, calculate the depth. Take Breadth = 10m .
A 10 m
B 5 m
C 8 m
D 12 m
If 'x' is the depth of flow in an open channel of large width, then the hydraulic radius is equal to
A x
B $$\frac{{\text{x}}}{2}$$
C $$\frac{{\text{x}}}{3}$$
D $$\frac{{2{\text{x}}}}{3}$$

Next steps