Related Questions

The most economical section of a trapezoidal channel is one which has hydraulic mean depth equal to
A $$\frac{1}{2}$$ × depth
B $$\frac{1}{2}$$ × breadth
C $$\frac{1}{2}$$ × sloping side
D $$\frac{1}{4}$$ × (depth + breadth)
A rectangular channel has cross sectional area of 50 m2 If the channel section is to be most economical, calculate the depth. Take Breadth = 10m .
A 10 m
B 5 m
C 8 m
D 12 m
The ratio of the depth of flow to the hydraulic radius for the most economical trapezoidal section, in open channel flow is
A 0.5
B 1
C 1.5
D 2
In open channel flow in a rectangular channel, the ratio between the critical depth and the initial depth, when a hydraulic jump occurs is
A 0.5
B 0.84
C 1.84
D 1.25
The ratio of width to depth for the most economical rectangular section in open channel flow is
A 0.5
B 1
C 1.5
D 2
The ratio of the hydraulic radius to the diameter of the channel, for maximum mean velocity of flow in a circular channel, in open channel flow is
A 0.3
B 0.9
C 0.03
D 0.66
The most economical channel section for the fluid flow is the one for which the discharge is maximum for a given cross-sectional area. Vertical velocity distribution in an open channel for laminar flow can be assumed to be
A Parabolic
B Hyperbolic
C Straight line
D None of these
The hydraulic mean depth or the hydraulic radius is the ratio of
A Area of flow and wetted perimeter
B Wetted perimeter and diameter of pipe
C Velocity of flow and area of flow
D None of these
Rectangular ABCD is similar to rectangular EFGH. The length of each side of rectangle EFGH is 24 times the length of corresponding side of rectangle ABCD.The perameter of rectangular ABCD is 120 feet.What is the parameter of rectangular paramaeter EFGH?
A 288feet
B 345.6feet
C 576feet
D 691.2feet
If 'x' is the depth of flow in an open channel of large width, then the hydraulic radius is equal to
A x
B $$\frac{{\text{x}}}{2}$$
C $$\frac{{\text{x}}}{3}$$
D $$\frac{{2{\text{x}}}}{3}$$

Next steps