Related Questions

The most economical section of a rectangular channel is one which has hydraulic mean depth or hydraulic radius equal to
A Half the depth
B Half the breadth
C Twice the depth
D Twice the breadth
The ratio of the depth of flow to the hydraulic radius for the most economical trapezoidal section, in open channel flow is
A 0.5
B 1
C 1.5
D 2
A rectangular channel has cross sectional area of 50 m2 If the channel section is to be most economical, calculate the depth. Take Breadth = 10m .
A 10 m
B 5 m
C 8 m
D 12 m
In open channel flow in a rectangular channel, the ratio between the critical depth and the initial depth, when a hydraulic jump occurs is
A 0.5
B 0.84
C 1.84
D 1.25
The ratio of the hydraulic radius to the diameter of the channel, for maximum mean velocity of flow in a circular channel, in open channel flow is
A 0.3
B 0.9
C 0.03
D 0.66
The most economical channel section for the fluid flow is the one for which the discharge is maximum for a given cross-sectional area. Vertical velocity distribution in an open channel for laminar flow can be assumed to be
A Parabolic
B Hyperbolic
C Straight line
D None of these
The ratio of width to depth for the most economical rectangular section in open channel flow is
A 0.5
B 1
C 1.5
D 2
The hydraulic mean depth or the hydraulic radius is the ratio of
A Area of flow and wetted perimeter
B Wetted perimeter and diameter of pipe
C Velocity of flow and area of flow
D None of these
A swimming pool is initially filled to a depth of 96 inches. After 2 weeks, the depth has decreased to9212 inches. Assuming that the depth decreased at a constant rate, after how many days would the water depth have reached 9334 inches?
A 3
B 9
C 7
D 6
The minimum size of stone that will remain at rest in a channel of longitudinal slope S and hydraulic mean depth R is given by
A 4RS
B 11RS
C 7RS
D 15 RS

Next steps