Fugacity and pressure are numerically equal, when the gas is

Fugacity and pressure are numerically equal, when the gas is Correct Answer In ideal state

We know the concept of fugacity is originated from the equation $$d{\mu _i} = pdv - sdT$$    for an pure gas.
Under constant temperature and assuming an ideal gas we can write this as $$d\mu = RTdlnP$$    and for an real gas the same equation is assumed keeping all the non-ideality in the term fugacity and written as $$d\mu = RTdlnf$$
So, we can say for an ideal gas $$f = p.$$
Bissoy MCQ

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