The activity of an ideal gas is numerically __________ its pressure.

A More than
B Less than
C Equal to
D Data insufficient, can't be predicted

Correct Answer: Equal to

Activity $$\left( a \right)$$ of a pure ideal gas is defined as:

$$a = \frac{{{\text{fugacity at an temperature and pressure of interest}}}}{{{\text{fugacity at same temperature and standard pressure }}}}$$

usually the, standard pressure $$=$$ 1 atm and for ideal gas fugacity at a temperature and pressure $$=$$ pressure at that conditions
So, $$a=P$$
Bissoy MCQ
#Chemical Engineering #Chemical Engineering Thermodynamics

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