The internal energy of an ideal gas does not change in a reversible __________ process.

The internal energy of an ideal gas does not change in a reversible __________ process. Correct Answer Isothermal

We know for an ideal gas the internal energy is given by:
Actually the internal energy (U) of any substance is a function of
$$\eqalign{ & dU = CvdT - \left \cr & {\text{For an ideal gas, }}PV = RT \cr & {\text{So, }}\left( {\frac{{\partial V}}{{\partial T}}} \right)p = \frac{R}{P}\,\,{\text{and }}\left( {\frac{{\partial V}}{{\partial P}}} \right)T = - \frac{{RT}}{{{P^2}}} \cr & {\text{Hence, }}dU = CvdT \cr} $$
So, in case of isothermal process the internal energy remains constant.
Bissoy MCQ

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