Internal energy of an ideal gas

Internal energy of an ideal gas Correct Answer None of these

Internal energy of an ideal gas is solely dependent on temperature and given by the relation: The internal energy of an substance is given by
$$\eqalign{ & dU = CvdT - \left \cr & {\text{For an ideal gas, }}PV = RT \cr & {\text{So, }}\left( {\frac{{\partial V}}{{\partial T}}} \right)p = \frac{R}{P}\,\,{\text{and }}\left( {\frac{{\partial V}}{{\partial P}}} \right)T = - \frac{{RT}}{{{P^2}}} \cr & {\text{Hence, }}dU = CvdT \cr} $$
So internal energy is only a function of temperature and increases with increase in temperature.
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