For a thermodynamic system containing 'x' chemical species, the maximum number of phases that can co-exist at equilibrium is

For a thermodynamic system containing 'x' chemical species, the maximum number of phases that can co-exist at equilibrium is Correct Answer X + 2

Since, phase rule is $$f\left( {{\text{degree of freedom}}} \right) = C - \emptyset + 2$$
Where, $$C=$$  number of components, $$\emptyset = $$  number of phases,
$$ \Rightarrow \emptyset = C - f + 2$$
So for maximum phases $$f$$ should be minimum $$f$$ cant be negative since it denotes number of variables hence $$f = 0$$
So, $$\emptyset = C + 2$$
Given $$C = X \Rightarrow \emptyset = X + 2$$
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