Number of degrees of freedom for a three phase system in equilibrium comprising of three non-reacting chemical species is
A
2
B
0
C
1
D
3
Correct Answer: 2
Given, number of phases $$\left( \emptyset \right) = 3$$Number of non-reacting components $$= 3$$
So, degree of freedom $$ = C - \emptyset + 2 = 3 - 3 + 2 = 2$$