Two substances are in equilibrium in a reversible chemical reaction. If the concentration of each substance is doubled, then the value of the equilibrium constant will be

A Same
B Doubled
C Halved
D One fourth of its original value

Correct Answer: Same

Consider an elementary reaction $$A \Leftrightarrow B$$   and let equilibrium concentrations of $$A$$ and $$B$$ be $${{C_a}}$$ and $${{C_b}},$$
So equilibrium constant $$\left( K \right)$$ is $${K_1} = \frac{{{C_b}}}{{{C_a}}}$$
When the concentrations of both the species doubled equilibrium constant becomes $$K = \frac{{2{C_b}}}{{2{C_a}}} \Rightarrow K = {K_1}.$$     Hence remains constant.
Bissoy MCQ
#Chemical Engineering #Chemical Engineering Thermodynamics

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