Fundamental momentum equation for a hydraulic jump, is

$${\text{D}}_1^2 - {\text{D}}_2^2 = \frac{{2{\text{q}}}}{{\text{g}}}\left( {{{\text{V}}_1} - {{\text{V}}_2}} \right)$$

$${\text{D}}_2^2 - {\text{D}}_1^2 = \frac{{2{\text{q}}}}{{\text{g}}}\left( {{{\text{V}}_1} - {{\text{V}}_2}} \right)$$

$${\text{D}}_1^2 - {\text{D}}_2^2 = \frac{{2{\text{q}}}}{{\text{g}}}\left( {{{\text{V}}_2} - {{\text{V}}_1}} \right)$$

$${\text{D}}_1^2 + {\text{D}}_2^2 = \frac{{2{\text{q}}}}{{\text{g}}}\left( {{{\text{V}}_2} - {{\text{V}}_1}} \right)$$

Fundamental momentum equation for a hydraulic jump, is Correct Answer $${\text{D}}_2^2 - {\text{D}}_1^2 = \frac{{2{\text{q}}}}{{\text{g}}}\left( {{{\text{V}}_1} - {{\text{V}}_2}} \right)$$

Bissoy MCQ Team

Civil Engineering
Irrigation Engineering

Fundamental momentum equation for a hydraulic jump, is

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