Related Questions

In a single stage, single acting reciprocating air compressor, without clearance volume, the work-done is minimum during
A Isothermal compression
B Isentropic compression
C Polytropic compression
D None of these
In a single acting reciprocating air compressor, without clearance, the compression of air may be
A Isothermal
B Polytropic
C Isentropic
D Any one of these
A large clearance volume in a reciprocating compressor results in
A Reduced volume flow rate
B Increased volume flow rate
C Lower suction pressure
D Lower delivery pressure
The minimum work required for a three stage reciprocating air compressor is ________ the work required for each stage.
A Equal to
B Double
C Three times
D Six times
By fitting an air vessel to the reciprocating pump, there is always a saving of work done and subsequently saving of power. This saving in case of a single acting reciprocating pump is
A 39.2%
B 48.8%
C 84.8%
D 88.4%
In a single acting reciprocating compressor, the suction, compression and delivery of air takes place in ________ of the piston.
A One stroke
B Two strokes
C Three strokes
D Four strokes
If the clearance ratio for a reciprocating air compressor is 'K', then its volumetric efficiency is given by
A $$1 - {\text{K}} + {\text{K}}{\left( {\frac{{{{\text{p}}_1}}}{{{{\text{p}}_2}}}} \right)^{\frac{1}{{\text{n}}}}}$$
B $$1 + {\text{K}} - {\text{K}}{\left( {\frac{{{{\text{p}}_2}}}{{{{\text{p}}_1}}}} \right)^{\frac{1}{{\text{n}}}}}$$
C $$1 - {\text{K}} + {\text{K}}{\left( {\frac{{{{\text{p}}_1}}}{{{{\text{p}}_2}}}} \right)^{\frac{{{\text{n}} - 1}}{{\text{n}}}}}$$
D $$1 + {\text{K}} - {\text{K}}{\left( {\frac{{{{\text{p}}_2}}}{{{{\text{p}}_1}}}} \right)^{\frac{{{\text{n}} - 1}}{{\text{n}}}}}$$
By fitting an air vessel to the reciprocating pump, there is always a saving of work done and subsequently saving of power. The saving in case of a double acting reciprocating pump is
A 39.2%
B 48.8%
C 84.8%
D 88.4%
The primary unbalanced force due to inertia of reciprocating parts in a reciprocating engine is given by (where m = Mass of reciprocating parts, $$\omega $$ = Angular speed of crank, r = Radius of crank, $$\theta $$ = Angle of inclination of crank with the line of stroke and n = Ratio of the length of connecting rod to radius of crank)
A $${\text{m}}{\omega ^2}{\text{r}}\sin \theta $$
B $${\text{m}}{\omega ^2}{\text{r}}\cos \theta $$
C $${\text{m}}{\omega ^2}{\text{r}}\frac{{\sin 2\theta }}{{\text{n}}}$$
D $${\text{m}}{\omega ^2}{\text{r}}\frac{{\cos2\theta }}{{\text{n}}}$$
The secondary unbalanced force due to inertia of reciprocating parts in a reciprocating engine is given by (where m = Mass of reciprocating parts, $$\omega $$ = Angular speed of crank, r = Radius of crank, $$\theta $$ = Angle of inclination of crank with the line of stroke and n = Ratio of the length of connecting rod to radius of crank)
A $${\text{m}}{\omega ^2}{\text{r}}\sin \theta $$
B $${\text{m}}{\omega ^2}{\text{r}}\cos \theta $$
C $${\text{m}}{\omega ^2}{\text{r}}\frac{{\sin 2\theta }}{{\text{n}}}$$
D $${\text{m}}{\omega ^2}{\text{r}}\frac{{\cos2\theta }}{{\text{n}}}$$

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