The discharge over a right angled notch is (where H = Height of liquid above the apex of notch)
A
$$\frac{8}{{15}}{{\text{C}}_{\text{d}}} \times 2{\text{g}} \times {\text{H}}$$
B
$$\frac{8}{{15}}{{\text{C}}_{\text{d}}} \times 2{\text{g}} \times {{\text{H}}^{\frac{3}{2}}}$$
C
$$\frac{8}{{15}}{{\text{C}}_{\text{d}}} \times 2{\text{g}} \times {{\text{H}}^2}$$
D
$$\frac{8}{{15}}{{\text{C}}_{\text{d}}} \times 2{\text{g}} \times {{\text{H}}^{\frac{5}{2}}}$$
Correct Answer: $$\frac{8}{{15}}{{\text{C}}_{\text{d}}} \times 2{\text{g}} \times {{\text{H}}^{\frac{5}{2}}}$$