Related Questions

The discharge over the trapezoidal notch is equal to the discharge over the rectangular notch __________ the discharge over the triangular notch.
A Plus
B Minus
C Divide
D None of these
The discharge over a right angled notch is (where H = Height of liquid above the apex of notch)
A $$\frac{8}{{15}}{{\text{C}}_{\text{d}}} \times 2{\text{g}} \times {\text{H}}$$
B $$\frac{8}{{15}}{{\text{C}}_{\text{d}}} \times 2{\text{g}} \times {{\text{H}}^{\frac{3}{2}}}$$
C $$\frac{8}{{15}}{{\text{C}}_{\text{d}}} \times 2{\text{g}} \times {{\text{H}}^2}$$
D $$\frac{8}{{15}}{{\text{C}}_{\text{d}}} \times 2{\text{g}} \times {{\text{H}}^{\frac{5}{2}}}$$
Rectangular ABCD is similar to rectangular EFGH. The length of each side of rectangle EFGH is 24 times the length of corresponding side of rectangle ABCD.The perameter of rectangular ABCD is 120 feet.What is the parameter of rectangular paramaeter EFGH?
A 288feet
B 345.6feet
C 576feet
D 691.2feet
If the head over the triangular notch is doubled, the discharge will increase by __________ times.
A 2
B 2.828
C 5.657
D 4
The discharge over a triangular notch is
A Inversely proportional to $${{\text{H}}^{\frac{3}{2}}}$$
B Directly proportional to $${{\text{H}}^{\frac{3}{2}}}$$
C Inversely proportional to $${{\text{H}}^{\frac{5}{2}}}$$
D Directly proportional to $${{\text{H}}^{\frac{5}{2}}}$$
The area of a rectangular field is 52000 sq. meters. This rectangular area has been drawn on a map to the scale 1 cm to 100 m. The length is shown as 3.25 cm on the map. The breadth of the rectangular field in the map is -
A 1.6 m
B 160 m
C 160 cm
D 1.6 cm
The discharge through a V-notch weir varies as
A $${{\text{H}}^{\frac{3}{2}}}$$
B $${{\text{H}}^{\frac{1}{2}}}$$
C $${{\text{H}}^{\frac{5}{2}}}$$
D $${{\text{H}}^{\frac{2}{3}}}$$
What is the value of included angle of a triangular notch for maximum discharge ?
A 30°
B 60°
C 90°
D 120°
The ratio of the discharge over a trapezoidal crest to a rectangular crest of Sarda falls of identical parameters, is
A 1.084
B 1.074
C 1.064
D 1.054
According to Francis formula, the discharge over a rectangular weir is (where n = Number of end contractions)
A $$\frac{2}{3} \times {{\text{C}}_{\text{d}}}\left( {{\text{L}} - {\text{nH}}} \right) \times \sqrt {2{\text{gh}}} $$
B $$\frac{2}{3} \times {{\text{C}}_{\text{d}}}\left( {{\text{L}} - 0.1{\text{nH}}} \right) \times \sqrt {2{\text{g}}} \times {{\text{H}}^{\frac{3}{2}}}$$
C $$\frac{2}{3} \times {{\text{C}}_{\text{d}}}\left( {{\text{L}} - {\text{nH}}} \right) \times \sqrt {2{\text{g}}} \times {{\text{H}}^2}$$
D $$\frac{2}{3} \times {{\text{C}}_{\text{d}}}\left( {{\text{L}} - {\text{nH}}} \right) \times \sqrt {2{\text{g}}} \times {{\text{H}}^{\frac{5}{2}}}$$

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