Related Questions

According to principle of transmissibility of forces, the effect of a force upon a body is
A Maximum when it acts at the center of gravity of a body
B Different at different points in its line of action
C The same at every point in its line of action
D Minimum when it acts at the C.G. of the body
If a given force (or a given system of forces) acting on a body __________ the position of the body, but keeps it in equilibrium, then its effect is to produce internal stress in the body.
A Change
B Does not change
C Changes periodically
D None of these
The change in length due to a tensile or compressive force acting on a body is given by (where P = Tensile or compressive force acting on the body, $$l$$ = Original length of the body, A = Cross-sectional area of the body and E = Young's modulus for the material of the body)
A $$\frac{{{\text{P}}l{\text{A}}}}{{\text{E}}}$$
B $$\frac{{{\text{P}}l}}{{{\text{AE}}}}$$
C $$\frac{{\text{E}}}{{{\text{P}}l{\text{A}}}}$$
D $$\frac{{{\text{AE}}}}{{{\text{P}}l}}$$
Whenever some external system of forces acts on a body, it undergoes some deformation. As the body undergoes some deformation, it sets up some resistance to the deformation. This resistance per unit area to deformation, is called
A Strain
B Stress
C Pressure
D Modulus of elasticity
In vibration isolation system, the transmissibility will be equal to unity, for all values of damping factor, if $$\frac{\omega }{{\omega {\text{n}}}}$$ is
A Equal to 1
B Equal to 2
C Less than 2
D Greater than 2
The transmissibility, for all values of damping factor, will be less than unity, if $$\frac{\omega }{{\omega {\text{n}}}}$$ is
A Equal to 1
B Less than 2
C Equal to 2
D Greater than 2
Dimensions of coefficient of transmissibility are
A M°L°T°
B M°L1T-1
C M°L2T-1
D M°L3T-1
If the resultant of two equal forces has the same magnitude as either of the forces, then the angle between the two forces is
A 30°
B 60°
C 90°
D 120°
Effect of a force on a body depends upon its
A Direction
B Magnitude
C Position
D All the above
A closely coiled helical spring is acted upon by an axial force. The maximum shear stress developed in the spring is $$\tau $$. The half of the length of the spring if cut off and the remaining spring is acted upon by the same axial force. The maximum shear stress in the spring in new condition will be
A $$\frac{\tau }{2}$$
B $$\tau $$
C $$2\tau $$
D $$4\tau $$

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