Related Questions

Two closely-coiled helical springs 'A' and 'B' are equal in all respects but the number of turns of spring 'A' is double that of spring 'B'. The stiffness of spring 'A' will be __________ that of spring 'B'.
A One-sixteenth
B One-eighth
C One-fourth
D One-half
Two closely coiled helical springs 'A' and 'B' are equal in all respects but the diameter of wire of spring 'A' is double that of spring 'B' The stiffness of spring 'B' will be __________ that of spring 'A'
A One-sixteenth
B One-eighth
C One-fourth
D One-half
Two closely coiled helical springs 'A' and 'B' are equal in all respects but the number of turns of spring 'A' is half that of spring 'B'. The ratio of deflections in spring 'A' to spring 'B' is
A $$\frac{1}{8}$$
B $$\frac{1}{4}$$
C $$\frac{1}{2}$$
D 2
Two closely-coiled helical springs 'A' and 'B' of the same material, same number of turns and made from same wire are subjected to an axial load W. The mean diameter of spring 'A' is double the mean diameter of spring 'B'. The ratio of deflections in spring 'B' to spring 'A' will be
A $$\frac{1}{8}$$
B $$\frac{1}{4}$$
C 2
D 4
A closely coiled helical spring is acted upon by an axial force. The maximum shear stress developed in the spring is $$\tau $$. The half of the length of the spring if cut off and the remaining spring is acted upon by the same axial force. The maximum shear stress in the spring in new condition will be
A $$\frac{\tau }{2}$$
B $$\tau $$
C $$2\tau $$
D $$4\tau $$
When two springs are in series (having stiffness K), the equivalent stiffness will be
A K
B $$\frac{{\text{K}}}{2}$$
C 2K
D $$\frac{{\text{K}}}{4}$$
When a closely-coiled helical spring of mean diameter (D) is subjected to an axial load (W), the deflection of the spring ($$\delta $$) is given by (where d = Diameter of spring wire, n = No. of turns of the spring and C = Modulus of rigidity for the spring material)
A $$\frac{{{\text{W}}{{\text{D}}^3}{\text{n}}}}{{{\text{C}}{{\text{d}}^4}}}$$
B $$\frac{{2{\text{W}}{{\text{D}}^3}{\text{n}}}}{{{\text{C}}{{\text{d}}^4}}}$$
C $$\frac{{4{\text{W}}{{\text{D}}^3}{\text{n}}}}{{{\text{C}}{{\text{d}}^4}}}$$
D $$\frac{{8{\text{W}}{{\text{D}}^3}{\text{n}}}}{{{\text{C}}{{\text{d}}^4}}}$$
A closely-coiled helical spring is cut into two halves. The stiffness of the resulting spring will be
A Same
B Double
C Half
D One-fourth
The capacity of a spring to store energy is called the spring form co-efficient. Stiffness of a spring is measured by the
A Ability to absorb shock
B Capacity to store energy
C Ratio of the wire & coil diameters
D Load to produce unit deflection
When a helical compression spring is cut into halves, the stiffness of the resulting spring will be
A Same
B Double
C One-half
D One-fourth

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